What is the mean and standard deviation of

63.7%?

What is the mean and standard deviation of
61.4%?

Using the 68-95-99.7 rule, describe the sampling distribution of 63.7%

Using the 68-95-99.7 rule, describe the sampling distribution of 61.4%?

Please help I am so lost...

In probability and statistics, mean is used to refer to one measure of the central tendency either of a probability distribution or of the random variable characterized by that distribution.

In statistics and probability theory, the standard deviation (represented by the Greek letter sigma, σ) shows how much variation or dispersion from the average exists. A low standard deviation indicates that the data points tend to be very close to the mean (also called expected value); a high standard deviation indicates that the data points are spread out over a large range of values.

So, how would I figure out the standard deviation of 61.4?

Z score is your score in arms of standard deviations.

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability (.6140) related to the Z score.

Are you assuming that the scores are equally distributed around the mean? Then you would want
± .307

1. Find the area associated with this section of the curve: between z = -1.15 and z = -1.35.

To find the mean and standard deviation of percentages, you need to know the sample size or total number of observations that the percentage represents. Without that information, it is not possible to calculate the mean and standard deviation accurately.

Regarding the sampling distribution using the 68-95-99.7 rule, this rule is a guideline based on the normal distribution. It states that for a normal distribution:

- Approximately 68% of the data falls within one standard deviation of the mean (mean ± 1 standard deviation).
- Approximately 95% of the data falls within two standard deviations of the mean (mean ± 2 standard deviations).
- Approximately 99.7% of the data falls within three standard deviations of the mean (mean ± 3 standard deviations).

If you provide the sample size or any additional information about the data, I can help you further.