Particle 1 with a momentum of 126.2 kg·m/s along the x axis, strikes particle 2, which is initially motionless. After the collision, particle 1 has an x component of momentum, p1x = 82.0 kg·m/s and a y component, p1y = 46.8 kg·m/s. What are p2x and p2y, the x and y momentum components of particle 2 after the collision?

To solve this problem, we can use the conservation of momentum. According to the law of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision.

Let's assume the masses of particle 1 and particle 2 are m1 and m2, respectively.

Before the collision:

The momentum of particle 1 along the x-axis (p1x) = 126.2 kg·m/s
The momentum of particle 2 along the x-axis (p2x) is initially zero (particle 2 is initially motionless).

So, the total momentum before the collision along the x-axis is:
p_initial_x = p1x + p2x = 126.2 kg·m/s + 0 kg·m/s = 126.2 kg·m/s

After the collision:

The momentum of particle 1 along the x-axis after the collision (p1x) = 82.0 kg·m/s
The momentum of particle 1 along the y-axis after the collision (p1y) = 46.8 kg·m/s
The momentum of particle 2 along the x-axis after the collision (p2x) = ?
The momentum of particle 2 along the y-axis after the collision (p2y) = ?

Using the law of conservation of momentum, we can write the equation for the total momentum along the x-axis:

p_initial_x = p_final_x
126.2 kg·m/s = 82.0 kg·m/s + p2x

Solving for p2x:
p2x = 126.2 kg·m/s - 82.0 kg·m/s
p2x = 44.2 kg·m/s

Now, let's consider the total momentum along the y-axis:

p_initial_y = p_final_y
0 kg·m/s = p1y + p2y
0 kg·m/s = 46.8 kg·m/s + p2y

Solving for p2y:
p2y = -46.8 kg·m/s

Therefore, the x-component of momentum for particle 2 after the collision (p2x) is 44.2 kg·m/s, and the y-component of momentum for particle 2 after the collision (p2y) is -46.8 kg·m/s.