According to the Current Population Survey of the Census Bureau, 67% of children live with both parents, 23% live with their mother only, and 5% live with their father only. The rest live with neither parent. If we choose a child at random, what is the probability that the child lives with only ONE parent (father OR mother)?
Either-or probabilities are found by adding the individual probabilities.
.23 + .05 = ?
.28
To calculate the probability that a randomly chosen child lives with only one parent (either their father or mother), we need to add the proportions of children living with their father only and children living with their mother only and then divide it by the total percentage of children.
Given that 67% of children live with both parents, 23% live with their mother only, and 5% live with their father only, we have:
Probability = (Percentage of children living with father only + Percentage of children living with mother only) / 100
Probability = (5% + 23%) / 100
Probability = 28% / 100
Probability = 0.28 or 28%
Therefore, the probability that a randomly chosen child lives with only one parent (father or mother) is 0.28 or 28%.