When Trevor and Brian play ping pong, the probability that Trevor will win is 0.6. If Trevor and Brian play two games of ping pong, find the probability that Trevor wins the first game and Brian wins the second. Assume games are independent. Give your answer as a decimal to two decimal places, e.g., 0.56

If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.

.6 * (1-.6) = ?

joe

To find the probability that Trevor wins the first game and Brian wins the second game, we need to multiply the probabilities of each event occurring.

Given that the probability Trevor wins a game is 0.6, the probability Brian wins a game is 1 - 0.6 = 0.4 (assuming no ties).

Since the two games are independent events, we can multiply the probabilities:
P(Trevor wins first game and Brian wins second game) = P(Trevor wins first game) * P(Brian wins second game)
= 0.6 * 0.4

Calculating this, we find that the probability Trevor wins the first game and Brian wins the second game is 0.24.

To find the probability that Trevor wins the first game and Brian wins the second game, we can multiply the probabilities of each event happening separately.

Given that Trevor's probability of winning a game is 0.6, the probability of Trevor winning the first game is 0.6.

Since the games are independent, the probability of Brian winning the second game is also 0.6.

To find the probability of both events happening, we multiply the individual probabilities:

0.6 * 0.6 = 0.36

Therefore, the probability that Trevor wins the first game and Brian wins the second game is 0.36.