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July 31, 2014

July 31, 2014

Posted by **Kelly** on Tuesday, October 15, 2013 at 9:54pm.

If the radius is changing at the rate of dr/dt =3ft/min, find the rate of change

of the area(dA/dt) at the moment in time when r = 16 ft

dA/dt=

- Calculus Homework -
**Reiny**, Tuesday, October 15, 2013 at 9:57pmA = πr^2

dA/dt = 2πr dr/dt

so when r = 16 ft and dr/dt = 3 ft/min

dA/dt = 2π(16)(3) ft^2/min

= 96π ft^2/min

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