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March 25, 2017

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Let A(t) be the (changing) area of a circle with radius r(t), in feet, at any time t in min.
If the radius is changing at the rate of dr/dt =3ft/min, find the rate of change
of the area(dA/dt) at the moment in time when r = 16 ft

dA/dt=

  • Calculus Homework - ,

    A = πr^2
    dA/dt = 2πr dr/dt

    so when r = 16 ft and dr/dt = 3 ft/min

    dA/dt = 2π(16)(3) ft^2/min
    = 96π ft^2/min

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