Tuesday

July 29, 2014

July 29, 2014

Posted by **Judith** on Tuesday, October 15, 2013 at 7:58pm.

Ignoring friction, what's the speed of the joined cars at the bottom of the incline?

What the first car's speed would have been at the bottom had it not struck the second car.

- PHYSICS -
**mariah**, Tuesday, October 15, 2013 at 8:29pmhomework

- PHYSICS -
**Jennell**, Thursday, October 17, 2013 at 1:41am38m*sin2.5°=1.66m

1.66/2=.829m <- 'halfway down'

v=Sqrt(2*9.81*.829)=4.03m/s

970*4.03=(970+1280)*V V=1.733m/s

.5(2250)(1.73)^2+2250*9.8*.829=21646.5 J

21646.5=.5(2250)(V)^2 V=4.39m/s

The speed of the joined cars is 4.39m/s

Sqrt(2*9.8*1.66)=5.7m/s

The first cars speed would have been 5.7m/s

I hope that wasn't too confusing.

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