Posted by **mdan** on Tuesday, October 15, 2013 at 11:54am.

Write the system as a matrix equation and solve using inverses.

x1 + 2x2 - x3 = -3

-2x1 - x2 + 3x3 = 0

-4x1 + 4x2 - x3 = -12

A. x1 = 2, x2 = -3, x3 = 1

B. x1 = 1, x2 = -2, x3 = 1

C. x1 = 1, x2 = -2, x3 = 0

D. x1 = 1, x2 = -3, x3 = 1

- maths -
**mdan**, Tuesday, October 15, 2013 at 11:54am
this one seems difficult...plz help

- maths -
**Steve**, Tuesday, October 15, 2013 at 12:10pm
You have an equation AX=B

where

A =

(1 2 -3)

(-2 -1 3)

(-4 4 -1)

and

B =

(-3)

(0)

(-12)

A^{-1} = 1/3 times

(11 10 -3)

(14 13 -3)

(12 12 -3)

So, X = A^{-1}B = (1,-2,0)

- maths -
**mdan**, Tuesday, October 15, 2013 at 12:32pm
fabulous

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