A solution of ethanol (C2H5OH) is prepared by dissolving 35.0 ml of ethanol in enough water to make 120.0 ml of solution. What is the molarity of the ethanol in this solution?

46.07 g= molar mass of ethanol
.079 g/ml=density

Sorry I meant .79= density

What's the mass of 35 mL ethanol. That will be mass = volume x density.

Then mols ethanol = grams/molar mass = ?
Finally M = mols/L solution.

To find the molarity of ethanol in the solution, we first need to calculate the number of moles of ethanol present in the given volume.

Step 1: Calculate the mass of ethanol in grams.
Since the density of ethanol is given as 0.079 g/ml, we can calculate the mass of 35.0 ml of ethanol using the formula:
mass = volume × density = 35.0 ml × 0.079 g/ml = 2.765 g

Step 2: Convert the mass of ethanol to moles.
To convert the mass of ethanol to moles, we need to divide the mass by the molar mass of ethanol.
molar mass of ethanol = 46.07 g/mol (given)
moles = mass / molar mass = 2.765 g / 46.07 g/mol ≈ 0.060 mol

Step 3: Calculate the molarity of the solution.
Molarity (M) is defined as moles of solute divided by the volume of solution in liters.
Given that the total volume of the solution is 120.0 ml, we need to convert it to liters by dividing it by 1000:
volume = 120.0 ml / 1000 = 0.120 L

Now we can calculate the molarity using the formula:
Molarity (M) = moles / volume = 0.060 mol / 0.120 L = 0.500 M

Therefore, the molarity of ethanol in the solution is 0.500 M.

23mol/l