Posted by Joy on .
Find the standard form of the equation of the parabola with the given characteristics and vertex at the origin. Passes through the point (-5, 1/8); vertical axis.
There is no focus of the parabola or equation given, so how am I suppose to solve this problem?
College Algebra -
Since the axis is vertical, you know it's
y = a(x-h)^2 + k
Since the vertex is at (0,0), you know that h=k=0, and thus
y = ax^2
1/8 = 25a
a = 1/200
y = 1/200 x^2
All the data you needed was there. Just gotta read it carefully.