Posted by **Joy** on Monday, October 14, 2013 at 3:33pm.

Find the standard form of the equation of the parabola with the given characteristics and vertex at the origin. Passes through the point (-5, 1/8); vertical axis.

There is no focus of the parabola or equation given, so how am I suppose to solve this problem?

- College Algebra -
**Steve**, Monday, October 14, 2013 at 4:22pm
Since the axis is vertical, you know it's

y = a(x-h)^2 + k

Since the vertex is at (0,0), you know that h=k=0, and thus

y = ax^2

1/8 = 25a

a = 1/200

so,

y = 1/200 x^2

All the data you needed was there. Just gotta read it carefully.

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