Posted by **Joy** on Monday, October 14, 2013 at 3:31pm.

Find the standard form of the equation of the parabola with the given characteristics and vertex at the origin. Passes through the point (-1, 1/8); vertical axis.

There is no focus of the parabola or equation given, so how am I suppose to solve this problem?

- College Algebra -
**Steve**, Monday, October 14, 2013 at 4:23pm
see the other solution I gave.

Same exact problem, just a different point.

- College Algebra -
** Henry**, Saturday, December 5, 2015 at 9:43pm
V(0,0), P(-1,1/8).

Y = a(x-h)^2 + k.

1/8 = a(-1-0)^2 + 0.

a = 1/8.

Y = 1/8(x-0)^2 + 0.

Y = (1/8)x^2.

## Answer This Question

## Related Questions

- College Algebra - Find the standard form of the equation of the parabola with ...
- Algebra - Suppose a parabola has an axis of symmetry at x = -2, a minimum ...
- college algebra - find the equation of a parabola that opens to the right with ...
- Algebra - An engineer designs a satellite dish with a parabolic cross section. ...
- Algebra - An engineer designs a satellite dish with a parabolic cross section. ...
- algebra - Suppose a parabola has vertex (-4,7) and also passes through the point...
- algebra - Suppose a parabola has a vertex (-4,7) and also passes through the ...
- Algebra - Please help I can't figure out these two. Express f(x) in the form a(x...
- Algebra 2 - Find the equation for the parabola with the given vertex that passes...
- pre cal - What is the center of the conic whose equation is x^2 + 2y^2 - 6x + ...

More Related Questions