How many grams of H2 are needed to produce 10.75g of NH3?
N2 + 3H2 ==> 2NH3
mols NH3 = grams/molar mass
Using the coefficients in the balanced equation, convert mols NH3 to mols H2.
Now convert mols H2 to grams. g = mols x molar mass
To determine the number of grams of H2 needed to produce NH3, we need to use the balanced chemical equation for the reaction. The balanced chemical equation for the formation of NH3 from H2 is:
N2 + 3H2 → 2NH3
From the balanced equation, we can see that 3 moles of H2 are required to produce 2 moles of NH3.
Step 1: Calculate the molar mass of NH3.
The molar mass of NH3 is:
M(N) + 3 × M(H) = 14.01 g/mol + 3 × 1.01 g/mol = 17.03 g/mol
Step 2: Calculate the number of moles of NH3.
Moles of NH3 = mass of NH3 / molar mass of NH3
Moles of NH3 = 10.75 g / 17.03 g/mol ≈ 0.63 mol NH3
Step 3: Calculate the moles of H2 needed.
Since 2 moles of NH3 require 3 moles of H2, we can set up a ratio:
2 moles NH3 / 3 moles H2 = 0.63 mol NH3 / x moles H2
Cross multiplying, we get:
2 × x = 0.63 × 3
2x = 1.89
x = 1.89 / 2
x ≈ 0.94 mol H2
Step 4: Calculate the grams of H2 needed.
Grams of H2 = moles of H2 × molar mass of H2
Grams of H2 = 0.94 mol × 2.02 g/mol ≈ 1.90 g
Therefore, approximately 1.90 grams of H2 are needed to produce 10.75 grams of NH3.
To solve this question, we need to use the balanced chemical equation for the reaction between hydrogen gas (H2) and ammonia (NH3):
N2 + 3H2 -> 2NH3
From the equation, we can see that 3 moles of hydrogen gas (H2) are required to produce 2 moles of ammonia (NH3).
Step 1: Convert grams of NH3 to moles
To begin, we need to convert the given mass of NH3 to moles using the molar mass of NH3. The molar mass of NH3 is:
1 atom of N = 14.01 g/mol
3 atoms of H = 3(1.01 g/mol) = 3.03 g/mol
Total molar mass of NH3 = 14.01 + 3.03 = 17.04 g/mol
For 10.75 g of NH3, we use the following conversion:
10.75 g NH3 * (1 mol NH3 / 17.04 g NH3) = 0.63 mol NH3
Step 2: Convert moles of NH3 to moles of H2
Next, we use the mole ratio from the balanced equation to convert moles of NH3 to moles of H2. The ratio from the equation is 3 moles of H2 for every 2 moles of NH3.
0.63 mol NH3 * (3 mol H2 / 2 mol NH3) = 0.945 mol H2
Step 3: Convert moles of H2 to grams of H2
Finally, we convert the moles of H2 to grams by multiplying with the molar mass of H2 which is 2.02 g/mol.
0.945 mol H2 * (2.02 g H2 / 1 mol H2) = 1.91 g H2
Therefore, approximately 1.91 grams of H2 are needed to produce 10.75 grams of NH3.