Wednesday

August 20, 2014

August 20, 2014

Posted by **HELP!!!** on Monday, October 14, 2013 at 1:47pm.

(a) Find the equivalent capacitance of the combination.

µF

(b) Find the potential difference across each capacitor.

(c) Find the charge on each capacitor.

- PHYSICS -
**Henry**, Tuesday, October 15, 2013 at 10:31pma. Ct = C1*C2?(C1+C2)

Ct = 7*11/(7+11) = 4.28 uF. = Total capacitance.

b. Qt = Ct*V = 4.28 * 9 = 38.5 uC=Q1=Q2

Q1 = C1*V1 = 38.5

7 * V1 = 38.5

V1 = 5.5 Volts.

C2 * V2 = Qt

V2 = 38.5/11 = 3.5 Volts.

c. Q1 = Q2 = Qt = 38.5 uC.

**Related Questions**

physics - lets say two capacitors C1 and C2 1uF each are connected in series ...

physics - lets say two capacitors C1 and C2 1uF each are connected in series ...

PHYSICS - Two capacitors are connected to a battery. The battery voltage is V = ...

Physics - Two fully charged capacitors (C1 = 2.00uF, q1=6.00uC,C2=8.00uF, q2 = ...

physics - Three capacitors with C1=C2=C3= 10.00 uF are connected to battery with...

Calculus - Second Order Differential Equations - Solve the initial-value problem...

Physics - Two capacitors are connected in parallel as shown above. A voltage V ...

Calculus - Second Order Differential Equations - Solve the boundary-value ...

Solve - Solve 1/C=1/C1 + 1/C2 for C1 This multiple choice and the listed answers...

Physics - The drawing shows two fully charged capacitors (C1 = 7 µF, q1 = 4 µC; ...