Wednesday

April 16, 2014

April 16, 2014

Posted by **Dee** on Monday, October 14, 2013 at 1:04pm.

- college algebra -
**Steve**, Monday, October 14, 2013 at 4:35pmIt's easier to work with

1/f(t) = 1/t + 1/(t+3)

For crew 1, 1/t = 1/24, so t=24

Thus 1/f(t) = 1/24 + 1/27 = 17/216

So, both crews can do it in 216/17 days

For crew 2, 1/(t+3) = 1/32, so t=29

Now 1/f(t) = 1/29 + 1/32 = 61/928

So, both crews can do it in 928/61 days

- college algebra -
**Dee**, Monday, October 14, 2013 at 7:48pmThank you Steve, that was a big help.

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