statistics
posted by eid2013 on .
Our statistics students, as noted were asked to rate their admiration of Hillary Rodham Clinton on a scale of 1 to 7. They also were asked to rate their admiration of Jennifer Lopez and Venus Williams on a scale of 1 to 7. As noted earlier, the mean rating of Clinton was 4.06, with a standard deviation of 1.70.The mean rating of Lopez was 3.72, with a standard deviation of 1.90. The mean rating of Williams was 4.58,with a standard deviation of 1.46. One of our students rated her admiration of Clinton and Williams at 5 and her admiration of Lopez at 4.
a. What is her z score for her admiration rating of Clinton?
b. What is her z score for her admiration rating of Williams?
c. What is her z score for her admiration rating of Lopez?
d. Compared to the other statistics students in our sample, which celebrity does this student most admire?(We can tell by her raw scores that she prefers Clinton and Williams to Lopez, but when we take into account the general perception of these celebrities, how does this student feel about them?)

Which value (1 or 7) is the high value?
A, B, C. Z = (scoremean)/SD
D. Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportions/probabilities related to the Z scores.