Posted by andres on .
Pete slides a crate up a ramp at an angle of 25◦ by exerting a 290 N force parallel to the ramp. The crate moves at a constant speed. The coefficient of friction is 0.28.
How much work did Pete do when the crate was raised a vertical distance of 2.24 m?
Answer in units of J
d = 2.24m/sin25 = 5.30 m Parallel to the
Work = Fex * d = 290 * 5.30 = 153t J.