When 51J of heat are added to 13g of a liquid, its temperature rises from 10.2 ∘ C to 12.6 ∘ C. What is the heat capacity of the liquid?
See your other heat problems.
q = mcdT
To find the heat capacity of a substance, we use the equation:
Heat capacity = (change in heat) / (change in temperature)
In this case, the change in heat is given as 51 J, and the change in temperature is the difference between the final and initial temperatures, which is (12.6 °C - 10.2 °C).
So, the change in temperature = 12.6 °C - 10.2 °C = 2.4 °C.
Now, we can substitute these values into the equation to find the heat capacity:
Heat capacity = 51 J / 2.4 °C
Calculating this gives us:
Heat capacity = 21.25 J/°C
Therefore, the heat capacity of the liquid is 21.25 J/°C.