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Posted by on Sunday, October 13, 2013 at 5:44pm.

A 660 kg car is being pushed along a flat parking lot at a constant speed of 1.52 m/s. The coefficient of friction between the road and the car is 0.31. What force is being used to push the car?

  • physics - , Monday, October 14, 2013 at 8:30pm

    Wc=M * g = 660kg * 9.8N/kg = 6468 N. =
    Weight of the car.

    Fex - Ff = m*a
    Fex - 0.31*6468 = m*0 = 0
    Fex = 2005 N. = Force exerted.

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