A 660 kg car is being pushed along a flat parking lot at a constant speed of 1.52 m/s. The coefficient of friction between the road and the car is 0.31. What force is being used to push the car?
Wc=M * g = 660kg * 9.8N/kg = 6468 N. =
Weight of the car.
Fex - Ff = m*a
Fex - 0.31*6468 = m*0 = 0
Fex = 2005 N. = Force exerted.
To find the force being used to push the car, we need to consider the balance between the force of friction and the force applied to overcome it.
Friction is determined by the coefficient of friction and the normal force. The normal force is the force exerted by the surface perpendicular to it, which is equal to the weight of the car in this case. The weight of the car can be calculated by multiplying the mass of the car (660 kg) by the acceleration due to gravity (9.8 m/s^2).
Weight = mass × acceleration due to gravity = 660 kg × 9.8 m/s^2
Next, we need to determine the force of friction using the formula:
Force of friction = coefficient of friction × normal force
Now that we have the force of friction, we know that the force applied to push the car must be equal and opposite (to maintain a constant speed). So, the force being used to push the car is equal to the force of friction.
Finally, we can substitute the values into the formula to find the force being used to push the car:
Force being used to push the car = Force of friction = coefficient of friction × normal force
Remember to use the correct units for the calculations.