Thursday
October 23, 2014

Homework Help: Chemistry

Posted by Chelsea on Sunday, October 13, 2013 at 2:25pm.

If a solution containing 52.044 g of mercury(II) chlorate is allowed to react completely with a solution containing 15.488 g of sodium sulfate, how many grams of solid precipitate will be formed? How many grams of the reactant in excess will remain after the reaction?

I have the balanced equation right I think...
Hg(ClO3)2+Na2SO4--->HgSO4(s) + 2NaClO3

Now I go from grams to moles of each element?

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Chemistry - If a solution containing 52.044 g of mercury(II) chlorate is allowed...
chemistry - If a solution containing 34.576 g of mercury(II) perchlorate is ...
Chemistry - If a solution containing 33.82 g of mercury(II) acetate is allowed ...
please help!! - If a solution containing 33.82 g of mercury(II) acetate is ...
chem please help! - If a solution containing 33.82 g of mercury(II) acetate is ...
basic chem - If a solution containing 33.82 g of mercury(II) acetate is allowed ...
chem really need help! - If a solution containing 33.82 g of mercury(II) acetate...
Chemistry - If a solution containing 118.44 g of mercury(II) perchlorate is ...
chemistry - write the balanced equation for the reactions of aquesous pb(CIO3)2 ...
chemistry - Calculate the theoretical yield of the precipitate formed when a ...

Search
Members