given equation of an ellipse as5x^2+3y^2-15=0.find center,foci,vertices andeccentricity andgraph
x^2/3 + y^2/5 = 1
a^2 = 3
b^2 = 5
so the long axis is vertical
c^2 = b^2-a^2 = 2
e = c/b = 2/5
foci at (0,±c)
a^2 = 3
b^2 = 5
so the long axis is vertical
c^2 = b^2-a^2 = 2
e = c/b = 2/5
foci at (0,±c)