Posted by ss01 on .
We will carry out some steps of the quantum factoring algorithm for N=91
(a) What is the period k of the periodic superposition set up by the quantum factoring algorithm if it chooses x=8? I.e. what is the period of f(j)=8j(mod91)
(b) Using your answer to (a), find a nontrivial square root of 1(mod91). Write your answer as an integer between 0 and 91.
(c) Then, the algorithm proceeds by computing gcd(91,y) for some y. What is y? If there are multiple correct answers, provide any one of them.

Quantum Physics 
realstein,
anyone,
please answer this. 
Quantum Physics 
Anonymous,
yes please..
and can anyone help with problem 1e? 
Quantum Physics 
Anonymous,
In q7 and 8 does all parts need to be correct... can anyone help please

Quantum Physics 
Anonymous,
for 1eI had XZ was wrong..sorry!

Quantum Physics 
ss01,
please help

Quantum Physics 
Anonymous,
does anyone know how to do q7? it seems this question requires all entries to be correct... have only 1 option left now?

Quantum Physics 
Naren,
I have all the solutions for ans. 5

Quantum Physics 
Naren,
5A) 1/sqrt(K), 1/sqrt(K)
5B) 1, 0
5C) 1/sqrt(K), 1/sqrt(K)
Make sure you enter the K as uppercase.
Please post whatever answers you get as well. 
Quantum Physics 
Naren,
2) pi

Quantum Physics 
Cyber,
Any one problem 6???

Quantum Physics 
Anonymous,
@Naren thanks for Q5.
Q6(a) is 4.. 
Quantum Physics 
Anonymous,
hi again... managed to do b... 64...
can anyone help with C... my last option left... plus q7 & q8 please 
Quantum Physics 
mk,
1(e)answer :z

Quantum Physics 
Anonymous,
Q6c and Q7, Q8 please!

Quantum Physics 
Anonymous,
help!!!

Quantum Physics 
Anonymous,
3b and c please!
3d is no 
Quantum Physics 
Anon,
3b  C
3c  0 
Quantum Physics 
Anonymous,
thx :)

Quantum Physics 
a,
6c can be calculated by answer to 6b  1

Quantum Physics 
mk,
6(b):64
6(c):63 
Quantum Physics 
Anonymous,
Q1, 7 and 8 please!

Quantum Physics 
mk,
1(a):z
1(b):x
1(c):x
1(d):z
1(e):z
1(f):x,x 
Quantum Physics 
Anonymous,
Thanks a lot

Quantum Physics 
Anonymous,
Q4 please!

Quantum Physics 
mk,
4(a):1 4(b):4
4(c):last option 
Quantum Physics 
mk,
Q:7&Q:8
PLEASE 
Quantum Physics 
Anon,
Q 7 and 8 Please!!!

Quantum Physics 
Abc,
Q7 and 8 please

Quantum Physics 
rs,
8a) theta=pi/3 and phi=0. this is 100% right. thanks guys

Quantum Physics 
Abc,
what about others, please help rs and others..........

Quantum Physics 
Cyber,
In this problem, assume that we are working in units such that ℏ=1. When providing Bloch sphere coordinates, please ensure that 0≤θ≤π and 0≤ϕ<2π whenever applicable.
8(a) Consider a spin qubit in the state 3√20⟩+121⟩. What are the coordinates (θ,ϕ) of this qubit on the Bloch sphere?
θ=?
ϕ=?
8b. We turn on a magnetic field in the z^ direction at time t=0. This corresponds to the Hamiltonian H=BZ, where B is a constant and Z is the usual phase flip. What is the state of our qubit at time t as a function of B and t?
8c. What are the coordinates (θ,ϕ) of this qubit on the Bloch sphere at time t, as a function of B and t?
8d. Now suppose we start with the qubit ψ(0)⟩=0⟩ and we apply a magnetic field in the x^ direction at t=0. This corresponds to the Hamiltonian H=BX, where B is a constant and X is the usual bit flip gate. What are the coordinates (θ,ϕ) of this qubit on the Bloch sphere at time t, as a function of B and t?
θ=?
ϕ=? 
Quantum Physics 
me,
Please 7 and 8b 8c 8d

Quantum Physics 
Anonymous,
anyone can help me with Q7 and 8b,c, d please.
Thanks for all who are trying to help each other. 
Quantum Physics 
rs,
hi, what about 1)d) it has two parts? which one is z and what is the other one?

Quantum Physics 
Anonymous,
@rs both parts are Z...
Do you have answer for q7 or 8 
Quantum Physics 
rs,
Thanks, I am working on 7 and 8. I have already posted for 8a). will post the rest as soon as it is done

Quantum Physics 
need help!,
on 7B answer is 2, ?, 8
Please i have the last submission to find out what insyead of "?". hope i helped you guys 
Quantum Physics 
Anonymous,
Thanks rs!

Quantum Physics 
Anonymous,
@needhelp ... how did you get 2, and 8

Quantum Physics 
Anonymous,
@Need help its 2, 9/2, 8.
do you have answer for q7a and C please..thanks 
Quantum Physics 
Anonymous,
anyone help please with q7(a)

Quantum Physics 
Anonymous,
8D please!

Quantum Physics 
Anonymous,
7A: momentum values 2, 3, 4
State for 3 is (0 1 0)
Got the seemingly correct values for 2
(1 0 i) and for 4 (1 0 i), but the system does not accept them. 
Quantum Physics 
Anonymous,
7A: momentum values 2, 3, 4
State for 3 is (0 1 0)
Got the seemingly correct states for 2
(1 0 i) and for 4 (1 0 i), but the system does not accept them. 
Quantum Physics 
Naren,
Great to see constructive collaboration here. I have got the same questions as most of you here. I do not have 3A; 7A, 7C; 8B, 8C, 8D. Can anyone help me out with these?
I see that someone is working on 7A. I will keep trying as well! 
Quantum Physics 
Anonymous,
3A  (1)^x  middle answer
8C  pi/3; 2*B*t 
Quantum Physics 
Anonymous,
Thanks for your help guys... what is q8(b. struggling with 7 as well.

Quantum Physics 
Anonymous,
Oy,
8b:
e^(i*B*t)*sqrt(3)/2
e^(i*B*t)/2
Do not tell anyone that I betrayed to you this great secret. 
Quantum Physics 
Anonymous,
Can anyone help with 8d and q7

Quantum Physics 
Anonymous,
thank you for the secret friend!!!

Quantum Physics 
Anonymous,
7B, again: 2, 9/2, 8.
7A: momentum values 2, 3, 4
State for 3 is (0 1 0)
Don't have anything more. 
Quantum Physics 
Anonymous,
Anyone done 8D? Please, I'm stuck there.

Quantum Physics 
a,
7c, t=pi > 1,0,0

Quantum Physics 
Anonymous,
Thanks "a" ..can you help with Q7(a)

Quantum Physics 
Anonymous,
7C complete answer:
0 0 1
1 0 0  pi rotation around x axis,
z> > z> 
Quantum Physics 
Anonymous,
Thanks...anon @4:37pm, can you also help with Q7A.. thanks

Quantum Physics 
Anonymous,
anyone can help me with Q7a and 8(d)..thanks...

Quantum Physics 
Anonymous,
I AM 90% SURE THAT THE ANSWER TO 8D IS:
theta: 2*B*t
phi: pi/2
CAN ANYONE PLEASE VERIFY THIS? I HAVE ONLY 1 CHECK LEFT... 
Quantum Physics 
Anonymous,
Yeah, that's not it the theta: 2*B*t
phi: pi/2 is wrong. 
Quantum Physics 
Anonymous,
It could be because 2*B*t is not in the [0,2*pi] range. Maybe it's theta = (2*pi  2*B*t) instead.
Anyone willing to try that? 
Quantum Physics 
ss01,
any other guesses?

Quantum Physics 
Quant,
I tried 2*pi2*B*t and pi/2, it was wrong :(

Quantum Physics 
Quant,
7A:
1/sqrt(2) , 0, i/sqrt(2)
2

0 , 1, 0
3

1/sqrt(2), 0, i/sqrt(2)
4

Any update on 8D? 
Quantum Physics 
rs,
for 8d i tried with this but got wrong
theta=2*B*t phi= 0 or pi/2 or pi 
Quantum Physics 
Kris,
8(d)
I tried everything... I can't get any value for 0<=thetha<=pi 
Quantum Physics 
Kris,
8(d)
the answer should be
thetha = 2*B*t
phi = pi/2
I tried thetha = 2*B*t, 2*pi2*B*t (although this mayn't be always between 0 and pi), 2*B*t (i know its wrong but i tried) 
Quantum Physics 
Anonymous,
The 8D answer with theta=2*B*t and phi=pi/2 is wrong!

Quantum Physics 
Kris,
Yes, I was trying to say it should be the answer, but the question required 0<=thetha<=pi...
this doesn't satisfy for any answers mentioned above by me...
I feel this question is tricky... can someone find the answer? 
Quantum Physics 
Anonymous,
Shouldn't the answer for 8d be as theta = pi/2 and phi = 2*B*t ? Can you confirm?

Quantum Physics 
Naren,
@Anonymous. That is not the answer; That is the same one I had got when I last tried. I've got 2 attempts left now.

Quantum Physics 
Anonymous,
can anyone help with Q8d please!

Quantum Physics 
jerome,
theta = pi (8D)

Quantum Physics 
Quant,
theta = pi
phi = pi/2
is wrong Jerome! How did you get theta = pi ??
I'm down to one try, so wait for a genuine answer for 8D 
Quantum Physics 
Anonymous,
Jerome, did you check the answer ?
theta=pi
What is phi then? 2*B*t ? 
Quantum Physics 
jerome,
Im certain theta is correct, unsure about phi. it is not B*t or 2bt. try 2bt

Quantum Physics 
Anonymous,
hi guys... have you got answer to Q8d.. I have now one option left only

Quantum Physics 
Anonymous,
Jerome, did you try ? Both answers must be correct in order to get check marks on both.

Quantum Physics 
jerome,
i tried theta = pi and phi = b*t
and theta = pi and phi = 2*b*t
try it with 2bt 
Quantum Physics 
Anonymous,
I tried:
theta = pi phi=B*t
theta = pi phi=2*B*t
Both incorrect. Down to the last answer. 
Quantum Physics 
Anonymous,
Could someone try:
theta = pi phi= 2*B*t ? 
Quantum Physics 
jerome,
8d) Theta = pi
Phi = 2*b*t 
Quantum Physics 
Anonymous,
Jerome, is this correct? I think somebody tried it and reported as incorrect, though the answer makes sense: X converts 0> to 1>, and 2*B*t is phi for 1>

Quantum Physics 
Anonymous,
Did anyone try
8d) Theta = pi
Phi = 2*b*t ? 
Quantum Physics 
Anonymous,
wrong

Quantum Physics 
Anonymous,
jerome wrong any one got answer for 8D

Quantum Physics 
jerome,
theta = pi
phi = 0 
Quantum Physics 
jason,
For 8d.
Theta = pi
Phi = 0 
Quantum Physics 
Anonymous,
I just tried what Jason said and it worked :)

Quantum Physics 
Anonymous,
I have helped with answers ...can someone help me with 8d...down with one option...I think both parts need to be correct...

Quantum Physics 
Anonymous,
pi and 0 work for 8d :)

Quantum Physics 
Anonymous,
I tried theta=pi and phi=0 its wrong!!!

Quantum Physics 
Anonymous,
Also tried theta = pi and phi = 0, its wrong. Anyone have any idea for 8d?

Quantum Physics 
Anonymous,
I tried what Jason said is working long time ago. It is wrong. I don't understand how it could have worked for you. Are you trolling ?

Quantum Physics 
Anonymous,
He must be trolling, lets ignore what jason and jerome say!

Quantum Physics 
Anonymous,
BTW, both parts must be correct.

Quantum Physics 
Anonymous,
What is the answer?! Someone make another question

Quantum Physics 
Anonymous,
please help with q8d please

Quantum Physics 
Anonymous,
can anyone help me with 8d please!!

Quantum Physics 
Anonymous,
It seems like some people experimenting at the expense of the others. A guy does not want to waste his trial, so he posts an answer he thinks is right as the correct answer. Then, he gets the feedback from those who unwittingly used their trials. Very mean, I say.

Quantum Physics 
Anonymous,
I think the answer is:
theta: pi/2
phi: (2*pi)(b*t) 
Quantum Physics 
Anonymous,
Only got 1 try, someone try that ^^^

Quantum Physics 
Anonymous,
Jason and Jerome please help with q8d!

Quantum Physics 
Anonymous,
@ Anonymous at 4:24pm
Your thinking is great. But did you try it? If not, why do you want the others to try? Could you give some background for your thinking ? 
Quantum Physics 
Anonymous,
Jason and Jerome are as much in darkness as we are.

Quantum Physics 
Anonymous,
theta=pi/2 and phi=2pibt is wrong!!

Quantum Physics 
Anonymous,
to those who have answers to Q8D..please can you help with explanation or your thoughts..thanks

Quantum Physics 
Anonymous,
8D Answer
theta = pi
phi = (2*pi)(B*t)
You are all welcome :) 
Quantum Physics 
Anonymous,
for pi and 0: X maps 0 to 1, meaning theta = pi. If it is at 0 or 1, then phi is irrelevant, could be 0, because 0 and 1 are along Z axis.

Quantum Physics 
Anonymous,
No the answer is:
theta = pi/2
phi = 0 
Quantum Physics 
Anonymous,
Anon @ 5:13  is it another bogus answer ?
What is the rationale for your answer ? 
Quantum Physics 
Anonymous,
@ Anonymous at 5:17:
BS, tried that long ago, wrong! 
Quantum Physics 
Anonymous,
As another anomyous @5:16 said, the answer would be theta = pi and phi= 0

Quantum Physics 
Anonymous,
help withq8d please someone out there!!!

Quantum Physics 
Anonymous,
The answer for 8d is theta = pi and phi = 0!!!!!

Quantum Physics 
Anonymous,
pi/2 and 0 are wrong!

Quantum Physics 
jerome,
Sorry about the mistake earlier i copied down the wrong answer, that was an answer from a previous attempt. The correct answer has already been stated on here.

Quantum Physics 
Anonymous,
Anonymous @5:44 PI is correct NOT pi/2

Quantum Physics 
Anonymous,
pi and 0 is also wrong!!

Quantum Physics 
Anonymous,
@Jerome ..what is the correct answer please!

Quantum Physics 
Anonymous,
@ Anonymous at 5:49:
He doesn't have a clue! He is just trolling... 
Quantum Physics 
Anonymous,
@Jerome..can you atleast explain how to get the answer please

Quantum Physics 
jerome,
Using the formula for the state psi under the act of a hamiltonian, you deduce that theta = pi and psi = bt. However the bt needs to be changed. think about why it needs to be changed

Quantum Physics 
Anonymous,
so is theta=pi and phi=2pibt

Quantum Physics 
Anonymous,
anyone please help with 8d..

Quantum Physics 
Anonymous,
theta=pi and phi=2pibt ISN'T WORKING

Quantum Physics 
Anonymous,
@Jerome thanks for the explanation so is the answer pi and 2pibt.. thank you

Quantum Physics 
Anonymous,
thanks @anon @7.09pm it also doesn't work for theta=pi and phi=2pi2bt...
HELP!! 
Quantum Physics 
Anonymous,
please help with 8d.

Quantum Physics 
Anonymous,
Jerome give the answer please!!

Quantum Physics 
Anonymous,
Just wondering has anyone got the answer for q8d..or am I the only one banging my head!!

Quantum Physics 
Anonymous,
help with q8D

Quantum Physics 
Anonymous,
did anyone already check for phi=2bt or 2b

Quantum Physics 
Anon,
Ive checked and its neither phi=2bt nor 2b

Quantum Physics 
Anonymous,
The answer is in both cases 0 and 0

Quantum Physics 
Anonymous,
No but almost! Pi and 0 works! Job done!!

Quantum Physics 
Anonymous,
pi and 0 does not work. Was tried long time ago. I doubt that 0, 0 would work either.

Quantum Physics 
Anonymous,
Jason, please stop trolling with your pi and 0 guano.

Quantum Physics 
ss01,
anyone plz try with 0 , 0
mine no chance left 
Quantum Physics 
Jason,
OK, here is the real answer:
theta = e*a*t
phi = s*H*i*t
Job done! 
Quantum Physics 
ss01,
@jason wonder did you really got the answer????????

Quantum Physics 
Cheaters,
Why not try yourself or insted give up? Only 4 points in a final exam of a whole course? Does it matter to get the Certificate? Is it so important? I assume that if you have been cheating the whole course doesn't matter not to get a 100% mark. Any explanation? If somebody gives a good explanation, I promise to give the correct answer.

Quantum Physics 
ss01,
ya okay maybe some people have cheated all the way through. But there may be a reason or so either to pass atleast the 80% mark because it is high cutoff and we have limited chances. Y people may do this?
To get certificate . Does certificate matters? Yes, may be they will use it in college to show off their intelligence or may be needed for some recommendation or will help them in some way....
There might be reason they can't solve all the problems infact only some get 100% mark and you wonder how much pass the 80% barrier? They might have wasted their 2 months or so........ 
Quantum Physics 
Anonymous,
We will get the certificate regardless, very well past that point. And we are not cheaters but rather the hard working overachievers. The problem is the suspense  we where studying so hard, what we have not learned so that nobody could answer that seemingly easy question ? What is the trick with that question ? Will we ever know ?
X turns 0> into 1>. So, theta is pi. Phi is the angle in the complex plane that is orthogonal to Z / Z axis where 0> and 1> lie. So, phi is not relevant. It could be 0, or anything.
Do you disagree with these conclusions ? Do you see any mistake ? 
Quantum Physics 
ss01,
sometimes you have to do wrong things to get into the right way may be for a cause or so

Quantum Physics 
MMM,
BTW, it is meaningless to talk about cheating in this course. The problems are not authentic. They are taken from a set of quantum mechanics/ quantum computing problems that is moving from a course to a course. Some "noncheaters" had no quarrel with the course because they have the answers to that set. So, we are just equalizing. Equal opportunities, that is the slogan.

Quantum Physics 
ss01,
@MMM you are correct!!!!!!!!

Quantum Physics 
Kris,
I bet "Cheaters" don't have answer to this question...

Quantum Physics 
ss01,
I think the answer is 0 & 0

Quantum Physics 
Jerome,
They will both be 0 because X is perpendicular to z so the field doesn't effect it. The transformation by X doesn't either because it is still around the z axis.

Quantum Physics 
ss01,
@jerome are you sure?

Quantum Physics 
Jerome,
Yes

Quantum Physics 
Anonymous,
0, 0 is wrong.

Quantum Physics 
ss01,
Jerome you are wrong, I think you also don't know the right answer. Stop fooling us around

Quantum Physics 
Anonymous,
Jerome is fooling you.
The actual answer is pi, pi. Jerome, go home. 
Quantum Physics 
Anonymous,
pi,pi seems to be wrong too.

Quantum Physics 
ss01,
Yup pi, pi is also wrong

Quantum Physics 
Anonymous,
Oh come on! pi pi/2. It is so eeeeeeeasy to see :D

Quantum Physics 
Anonymous,
Nope, pi and pi/2 also wrong.

Quantum Physics 
Anonymous,
Ha ha! Correct answers told as wrong. The good answer was already given and now the question: who is fooling who?

Quantum Physics 
ss01,
plz tell what is the answer?

Quantum Physics 
Jerome,
The answer, my friend, is blowin' in the wind, the answer is blowin' in the wind.

Quantum Physics 
ss01,
there are various answers and only 2 chances, what you think will be the probability?

Quantum Physics 
Anonymous,
0<p<1, or something like that

Quantum Physics 
ss01,
P>0

Quantum Physics 
ss01,
come on please please please please please please please please please tell the right answer

Quantum Physics 
Jerome,
Since phi is irrelevant, you must leave it blank. The grader is intelligent and will mark it as correct.

Quantum Physics 
ss01,
what nonsense is this? if you so intelligent then what is theta?
i have never seen not putting any value and getting it correct 
Quantum Physics 
Jerome,
Well try it and you'll see.

Quantum Physics 
ss01,
so atleast tell what is theta?
if you r right i would worship you 
Quantum Physics 
Jerome,
OK, theta is f*a*r*t/2

Quantum Physics 
Jerome,
This is a special optimization question.
You just leave both fields blank and click submit. The grader will figure the correct answer for you for theta, and will simply mark the blank phi as correct.
try this! 
Quantum Physics 
ss01,
what are f, a & r ???

Quantum Physics 
Jerome,
You know where it is coming from, don't you?

Quantum Physics 
ss01,
nope!!!!!!

Quantum Physics 
Jerome,
It is coming from the expression:
(1/(sqrt(s*H*i*t)))*(p*o*o*p) 
Quantum Physics 
ss01,
you are wrong this too :D :D :D

Quantum Physics 
Anonymous,
@Jerome stop being mean, if you can help that's fine if cant please don't confuse us!!!

Quantum Physics 
quantum,
theta = pi
phi = 0
got 100% 
Quantum Physics 
Anonymous,
pi and 0 is wrong...I wonder how you got 100%

Quantum Physics 
quantum,
it is not wrong, do not fool around

Quantum Physics 
Anonymous,
0 and 0 is wrong!

Quantum Physics 
Anonymous,
I checked 0 and 0 its marked wrong!

Quantum Physics 
anky,
final ans of 8D plzzzzzz!!!

Quantum Physics 
Anonymous,
@quantum...I have checked and it was wrong...you stop fooling around mate!!!thanks for yr sharing anyway!

Quantum Physics 
quantum,
You're welcome. Does this mistake made you don't pass the course? Come on... is this the case?

Quantum Physics 
Anonymous,
@ quantum.. actually I passed ... even if you have 100% does it matter! have some self pride mate!!

Quantum Physics 
Anonymous,
so you admit you put the wrong answer on purpose!!! don't you feel guilty quantum?

Quantum Physics 
Anonymous,
don't feed the troll ;)
back to topic.. I have two submissions left but no more ideas.. 
Quantum Physics 
Anonymous 234,
I am working on an idea! Anonymous @4:33pm wait for me to answer again and then try it for me please :)

Quantum Physics 
Anonymous,
what's your idea @4H34 ?

Quantum Physics 
Anonymous 234,
Have to change 0> to +> and > equivalents and then simplify from there on in.

Quantum Physics 
Anonymous,
@quantum I am pretty sure you must have used one of our answers at some point in this course!! you know what... no one is perfect!!

Quantum Physics 
Anonymous,
annon 234, why that ?

Quantum Physics 
Anonymous 234,
@4:46 because the X bit flip acts in those eigenvectors.
I think the answer is as follows:
theta = pi/2
phi = B*t
Now i am not 100% on phi; it may be 2*B*t 
Quantum Physics 
Anonymous 234,
Phi would be 2*B*t!!!

Quantum Physics 
Anon,
Wrong !!!! I try it!!

Quantum Physics 
Anonymous,
@234, havn't tried, only one try left
physics.stackexchange dot com/questions/81101/quantumcomputationhamiltonian
maybe some hints 
Quantum Physics 
pari,
@ anyone... can anyone help with Q8D please!!!

Quantum Physics 
Jerome,
pi/2 B*t and 2*B*t were tried long time ago, and failed. Anons 234 idea about conversion of 0> to +> / > basis was tried and yielded e^(2Bt)1>. The grader does not take that answer equivalent to pi 2Bt.

Quantum Physics 
pari,
@ Jerome...why are you even here when you have the right answer!!1

Quantum Physics 
Anonymous,
@ Jason and Jerome does not have any clue...check new postings guys and don't be fooled!

Quantum Physics 
Anonymous,
it seems now that the answer is very simple... but what is it?

Quantum Physics 
pari,
help please!!!

Quantum Physics 
Trust me,
I am incredibly close to the answer. Will update soon!

Quantum Physics 
pari,
pi/2 and Bt is wrong guys...just tried... down to my last option... help!

Quantum Physics 
Anonymous,
guys don't trust anyone..trust yr instincts...

Quantum Physics 
Trust me,
The answer is theta = 0 and phi = 2pi !!!!
I can leave this question forever now!! 
Quantum Physics 
Anonymous,
No....
theta=0 and phi=2*pi 
Quantum Physics 
Anonymous,
Theta=2BT
Phi=pi/2 
Quantum Physics 
Anonymous,
Thankyou Anonymous @ 7:08 it worked

Quantum Physics 
Anonymous,
theta = 2bt
phi = 0 
Quantum Physics 
Anonymous,
which one is right: theta: 2Bt and pi/2 or 2bt and 0!!! please help!!

Quantum Physics 
Anonymous,
Theta=2BT
Phi=pi/2 
Quantum Physics 
Anonymous,
It works at last!

Quantum Physics 
Anonymous,
really it doesn't and did not work for me mate!!

Quantum Physics 
Anonymous,
No, it is not. All troll answers are wrong.

Quantum Physics 
2013,
seriously anyone has any help to offer for q8d

Quantum Physics 
Anonymous,
help please with q8d

Quantum Physics 
Anonymous,
what works guys for 8d

Quantum Physics 
Jason,
For $1000, I'd give you the right answer.

Quantum Physics 
ss01,
done
but if it is wrong we would take 1000 from you 
Quantum Physics 
Jason,
So, are you ready to transfer them to my personal account at the Bank of Nigeria ?

Quantum Physics 
Jason,
Time is running out for you. No money means no score sufficient to get the certificate.

Quantum Physics 
Anonymous,
The answer is theta = 0 and phi = 2Bt
everyone stop being mean to the people who want the answer 
Quantum Physics 
ss01,
yup,
1000 USD done...... 
Quantum Physics 
Anonymous,
Theta is not 0 and phi is not 2*B*t

Quantum Physics 
david,
jason what happened?

Quantum Physics 
david,
seems you are doing a nice deal out here

Quantum Physics 
Anonymous,
Confirmation of theta = BT and Phi = pi/2

Quantum Physics 
ss01,
you asking us to confirm or telling the answer?

Quantum Physics 
Anonymous,
sorry theta = 0, not bt!
theta = 0 and hphi = pi/2 
Quantum Physics 
ss01,
are you sure???
i will give jason's deal to you 
Quantum Physics 
Anonymous,
I am fairly certain that it is

Quantum Physics 
Anonymous,
can you explain how you got theta = 0 and phi = pi/2

Quantum Physics 
ss01,
did you try it?

Quantum Physics 
Anonymous,
So, phi = pi/2 always, independent on time and the strength of the field ?
Hmm, maybe, maybe, because the perpendicular field separates the spin upwards/downwards. Though, I'm still skeptical. 
Quantum Physics 
Anonymous,
Citation:
"How can we create a beam of qubits in the state ψ=0? Pass a beam of spin1/2
particles with randomly oriented spins through a SternGerlach apparatus oriented along the z axis. Block the downwardpointing beam, leaving the other beam of 0 qubits. 
Quantum Physics 
ss01,
you try it and send us a screenshot of you r page

Quantum Physics 
Anonymous,
Guys, simply read this, pages 2 & 3
inst.eecs.berkeley.edu/~cs191/fa07/lectures/lecture15_fa07.pdf 
Quantum Physics 
Anonymous,
theta = 0 and phi = pi/2 is wrong
theta = pi/2 and phi = 0 is also wrong 
Quantum Physics 
Anonymous,
So, here is my rationale. +> and > are two eigenvectors of X, with eigenvalues of 1 and 1. So, putting them through X makes them unchanged, bar reversal of >.
0> = 1/sqrt(2)+> + 1/sqrt(2)>
That is the output:
X*0> = 1> = 1/sqrt(2)+>  1/sqrt(2)>;
Canonical form:
Psi(x) = cos (theta/2)+ e^(i*phi)sin (theta/2):
Now, how do we get from canonical form to 1> output ?
Easy:
theta/2 = pi/4, thus theta = pi/2;
e^(i*phi)= 1 iff phi = 0
So the answer should be theta = pi/2
and phi = 0.
Generally speaking, the magnetic field performs Bloch sphere rotation/transposition along the axis it is applied. Therefore, application along x axis transforms 0> into 1>
I don't remember if theta = pi/2
and phi = 0 was ever tried. But, rationally, that should be the answer.
P.S. I cannot try, down to the last submission. 
Quantum Physics 
Anonymous,
I see above that theta = pi/2
and phi = 0 were tried. Maybe, the grader is not programmed it correctly ? Did anyone really got his 8D answer accepted? 
Quantum Physics 
ss01,
if you so sure please risk yourself and tell us

Quantum Physics 
Anonymous,
Theta = 2bt
Phi = 3pi/2 
Quantum Physics 
chop,
Found the same result but don't beleive in it. ;)

Quantum Physics 
ss01,
@chop are you sure???

Quantum Physics 
chop,
I am quite sure

Quantum Physics 
chop,
No. I'm not sure. Really. Looks like it's wrong result.

Quantum Physics 
chop,
Fake @chop detected!

Quantum Physics 
ss01,
what is going on????

Quantum Physics 
chop,
theta = 2bt
phi = pi 
Quantum Physics 
ss01,
what is phi tell properly

Quantum Physics 
chop,
phi is pi!!

Quantum Physics 
ss01,
did you got it correct?

Quantum Physics 
chop,
Yes i did.

Quantum Physics 
ss01,
could you send a screenshot of it????

Quantum Physics 
chop,
Cant send screen shots on here :/

Quantum Physics 
ss01,
take a screen shot and upload on bit and paste the link without http if u r confident about your answer and your intelligence

Quantum Physics 
Anonymous,
i.minus dot com/i5xld8aUe08Ee.png
I CAN 
Quantum Physics 
ss01,
ya good screenshot is of wrong answer

Quantum Physics 
ss01,
anyone confident of answer please send screenshot

Quantum Physics 
jerome,
Theta = 2bt
Phi = pi/2
imgur dot com/eMrPvfk 
Quantum Physics 
Anonymous,
Jerome  fake! fake screen shot!

Quantum Physics 
ss01,
@jerome yup its fake

Quantum Physics 
Anonymous,
YEap, if you see this thread, you will see that they ask if someone has mixed phi with theta as he give an answer Theta=pi/2 a Phi=2bt. It's only matter of reading you cheaters.
physics.stackexchange dot com/questions/81101/quantumcomputationhamiltonian 
Quantum Physics 
ss01,
@anonymous please try and send a fake screenshot

Quantum Physics 
jerome,
Theta=pi
Phi=s*o*B 
Quantum Physics 
Anonymous,
@jerome
i.minus dot com/i9iaY1QUADBkO.png
You managed to fail your fake... congrats. 
Quantum Physics 
Anonymous,
please help if you can with Q8d

Quantum Physics 
Pari,
Hi guys... I just tried:8d
theta: 2*B*t and phi: 3*pi/2 and it worked!!
thanks to those who helped... 
Quantum Physics 
jerome,
@Pari. Another fake ? Where did you get theta: 2*B*t and phi: 3*pi/2 from ?

Quantum Physics 
Anonymous,
Yah fake too :(

Quantum Physics 
Pari,
No, it is real, though I forgot the sign:
theta: 2*B*t and phi: 3*pi/2 
Quantum Physics 
Anonymous,
fake

Quantum Physics 
Anonymous,
there is no point in faking when you can always create a new account and get an extra 3 tries(I hope you guys aren't trying these on your actual accounts).
Why not just stick to solving the problem.
I'm trying to do it like I did 8C but it's just not working.
The rotation about the xaxis changes phi to theta and theta to phi. 
Quantum Physics 
Pari,
My answer is correct...take it or leave it ...Q8d theta:2*B*t and phi 3pi/2..stop using my name...and confusing others...guys trust me... and stop This is my last post... anyone using pari is fake!!!I am going to report those using my name!!

Quantum Physics 
Anonymous,
thx Pari :)

Quantum Physics 
Anonymous,
Fake again...

Quantum Physics 
Pari,
fake Pari, or whatever it was, fake answer.
If you claim you are real, explain how you arrived to that answer, pleeeeazeee 
Quantum Physics 
ss01,
I tried theta = 2*B*t and phi = (3*pi)/2
AND IT WORKED
THANKYOU SO MUCH Pari!! 
Quantum Physics 
rs,
@ss01, is theta= 2*B*t or 2*B*t?

Quantum Physics 
ss01,
Its 2*B*t

Quantum Physics 
rs,
YES IT WORKED, THANK YOU GUYS
THETA= 2Bt and phi= 3pi/2 
Quantum Physics 
Anonymous,
Thanks Pari and SS01...we all know who the fake Pari may be?
so its... theta= 2*B*t and phi= (3*pi)/2
Thanks to also everyone who helped through out!! 
Quantum Physics 
Anonymous,
i dunno how m stuck with 8c. :(
i need help. 
Quantum Physics 
Anonymous,
You find the all answers somewhere in this thread:
8:
A: pi/3 0
B: e^(i*B*t)*sqrt(3)/2 e^(i*B*t)/2
C: pi/3 2*B*t
D: 2*B*t 3*pi/2
Thanks a lot for 8D 
Quantum Physics 
Anonymous,
Thanks Pari. Still, I wonder, how did you arrive to the correct answer? Seems that I missed something in the course.

Quantum Physics 
Pari, Jerome,
"why are you faking ..."
I'm a TA. It was entertaining to observe you cheating. So, we have decided that those of you who entered the answer within 6 hours after publication on this site will not get a completion certificate, because of academic dishonesty. The dishonesty policies and the conditions for the course completion were published rather prominently on the course site. Cheating in EDX courses will not be tolerated. 
Quantum Physics 
Rhunt,
How will you find out who gave the answers by cheating and who actually solved each answer.
Some of us actually solve the answers out on paper and plug it in to the autograder.
A few of us haven't even shared a single answer and were just here for entertainment purposes.
I think you are either trolling or bluffing. Have fun with the complaints from testtakers who entered answers correctly. 
Quantum Physics 
Pari, Jerome,
We have your IP addresses. If you visited the page for "entertainment purposes", and then entered the answer stated on this page within 6 hours after your visit, you clearly cheated. Since the "entertainment purposes" of your visit included the forbidden collaboration on the problems, you violated the terms of the course, and you will receive no certificate.

Quantum Physics 
victor,
thnx frnds, all of you :)

Quantum Physics 
Rhunt,
Your method of using IP addresses would never work. Most people here have static Ip's ,unless you have a corporate connection; everyone's IP address would change the moment they restart their modem.
Obtaining the Ip address for each comment here is clearly impossible.This site does not store ip addresses and attempting to find it is illegal.
I would have to report you for performing illegal acts on behalf of EdX.
Performing such a task of filtering IP addresses on Edx's server would require admin access to the server files which you don't have and can not get because you would have to be the admin.
I don't care about the certificate; just wanted to learn. If you are confident you can find IP addresses for every person then do so and tell me which country I live in. troll. 
Quantum Physics 
Pari, Jerome,
You don't understand how it works. You will be up to an unpleasant surprise, cheater. If you took the course just to learn, you had no business to cheat. As Mark said, the final exam was very straightforward if you studied in earnest. Since you had to resort to cheating, it appears that you have not learned much.

Quantum Physics 
Rhunt,
I discourage cheating, I haven't even given the final exam, I'm just auditing the course. (just to learn)
I'm just proving that your ideology and methodology is wrong. You could really mess up the EdX system if you decided to do it your way.
You can't see what visitors were seeing before visiting your website(EdX). Having the Ip address would mean nothing since you can't view visitors' browsing history.
I still challenge you to find what country I'm in (I don't care if you get all my ISP's details; I'll just restart my modem). If you can do it, then I'll back out and let you proceed while I make better use of my time. 
Quantum Physics 
Pari, Jerome,
You let me to proceed ? That is most interesting. Thank you, sahib, I'm patiently waiting for your kind permission.

Quantum Physics 
Rhunt,
Love the sarcastic comment. This is the best entertainment I've received throughout the entire duration of this publication.