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February 28, 2015

February 28, 2015

Posted by **mdan** on Saturday, October 12, 2013 at 11:05am.

A. C = 45x + 65

B. C = 65x + 45

C. 65x + 45C = 0

D. 45x + 65C = 0

A business purchases a copier for $5,500 and anticipates it will be worth $2,500 after 10 years. Use straight-line depreciation to find a linear model for the depreciated value V of the copy machine after t years of use.

A. V = -5,500 + 300t

B. V = 300 - 5500t

C. V = -300 + 5500t

D. V = 5,500 - 300t

- maths -
**Steve**, Saturday, October 12, 2013 at 11:09am#1. Since there is a fixed charge of $65, you know that there will be a "...+65" in the solution. That leaves only (A)

#2 Since the value starts at $5500, you know the solution will have "5500-..." in it. That leaves only (D)

See whether you can justify the rest of the solution.

- maths -
**Kelsi**, Saturday, October 12, 2013 at 11:13amA for the 1st one, 45 dollars per hour, x, is 45x. The fixed-service is a one-time thing so it's c = 45x + 65.The 2nd one is D. The original cost of the copier is 5,500. 5500-2500 = 3000. This is the cost reduction over the ten years. 3000/10 is 300: The amount it gets reduced by every year. For D, when you plug in 10, you get 2,500.

- maths -
**mdan**, Saturday, October 12, 2013 at 11:22amthanks much Steve and Kelsi

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