AP Chemistry
posted by Gabriella on .
How much work is done by the system when
2.00 moles of O2 expand from a volume of
3.00 liters to a volume of 9.6 liters against a constant external pressure of 0.0100 atm
answer in units of joules

w = pdV
Work done by the system is 
pdV is 0.01*(9.66.6) 
where did you get the 6.6 from? and i did the work correctly and the answer was wrong.

I typed in the wrong number. That's V2V1 = (9.63.00) so
work = 0.01*6.6 = ? in L*atm since 0.01 is in atm and delta V is L. The problem asks for joules. Convert L*atm to Joules.
1 L*atm = 101.325 joules. 
This may be a little late but what about moles