Question

If the visible part of an ice berg is 50mx50m in area and 20m is above the surface, what is the height, h?

I tried using FB=FG but I don't get anywhere. Can anyone help me out?

Answer 1

mg=F(buo)

ρ(ice)V₁g = ρ(water)V₂g
ρ(ice)•50•50•h•g = ρ(water) •50•50•(h-20) •g
ρ(ice)• h = ρ(water) • (h-20)
917•h=1000(h-20)
h=241 m
Above the water surface 241-20 =221 m