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April 18, 2015

April 18, 2015

Posted by **Sarah** on Friday, October 11, 2013 at 3:45am.

Determine the stopping distances for an automobile with an initial speed of 89 km/h and human reaction time of 2.0 s for the following:

(a) an acceleration a = -4.0 m/s2.

(b) a = -8.0 m/s2.

- Physics -
**Elena**, Friday, October 11, 2013 at 4:54pmv=89 km/h=89000/3600= 24.7 m/s.

The distance covered during the reaction time is

s₁=v₀t₁=24.7•0.2=49.4 m

The distance covered during braking s₂

s₂=v₀t₂-at₂²/2

v=v₀-at₂

v=0 =>

t₂=v₀/a

s₂=v₀²/2a =24.7²/2•4=76.3 m

s=s₁+s₂ =49.4+76.3 =125.7 m

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