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April 24, 2014

Homework Help: chemistry

Posted by Anonymous on Friday, October 11, 2013 at 3:33am.

A solution contains 10.05 grams of an unknown covalent substance in 50.0
grams of water. The freezing point of this solution is (-) 3.16o C.
What is the formula weight of the unknown compound?

Below is what I tried, but don't know what to do next. Please explain step-by-step. Thanks

m=3.16/1.86=1.69 moles of solute/kg of water. 10.05 x 1000*50 g/kg of water is 200.4 g. So in l liter we have 1.69 moles = 200.4g. Mass of 1 mole =200.4/1.69 = 118.59

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