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November 22, 2014

November 22, 2014

Posted by **Jen** on Friday, October 11, 2013 at 12:58am.

What is the minimum centripetal acceleration the SUV must have in going around the circular curve to clear the gully and land on the other side?

This is how I attempted the problem: please tell me what I did wrong.

y = 1/2*g*t^2 or t= sqrt(2*y/g) = sqrt(2*2.96/9.80) = 0.777s

So the speed needed to cross the gully is vx = x/t = 10.0m/0.777s = 12.87m/s

Now the centripetal acceleration would be v^2/r = 12.87^2/333m= 0.497m/s^2

- physics -
**Jen**, Friday, October 11, 2013 at 1:09amNevermind, I realized my mistake. I forgot to add the length of the SUV (4.00 m) to 10.0 m.

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