Posted by **Jen** on Friday, October 11, 2013 at 12:58am.

For a scene in a movie, a stunt driver drives a 1.50×10^3kg SUV with a length of 4.00m around a circular curve with a radius of curvature of 0.333 km. The vehicle is to be driven off the edge of a gully 10.0 m wide, and land on the other side 2.96 m below the initial side.

What is the minimum centripetal acceleration the SUV must have in going around the circular curve to clear the gully and land on the other side?

This is how I attempted the problem: please tell me what I did wrong.

y = 1/2*g*t^2 or t= sqrt(2*y/g) = sqrt(2*2.96/9.80) = 0.777s

So the speed needed to cross the gully is vx = x/t = 10.0m/0.777s = 12.87m/s

Now the centripetal acceleration would be v^2/r = 12.87^2/333m= 0.497m/s^2

## Answer this Question

## Related Questions

- Physics - For a scene in a movie, a stunt driver drives a 1.50x10^3 kg SUV with ...
- Physics - For a scene in a movie, a stunt driver drives a 1.50×103kg SUV with a ...
- Physics - For a scene in a movie, a stunt driver drives a 1.40x10^3 kg pickup ...
- Physics I'm so Lost!! - For a scene in a movie, a stunt driver drives a 1.90 103...
- Physics - For a scene in a movie, a stunt driver drives a 1.90 103 kg pickup ...
- physics - A car drives along a road section free of curves with speed v0 first ...
- Physics - A race car driver drives her 1500 kg car around a circular turn, which...
- physics - Posted by sandhu on Wednesday, November 24, 2010 at 4:29am. The ...
- Physics - A car drives around a curve with radius 150 m at a speed of 30 m/s. ...
- Physics - The fast French train known as the TGV (Train à Grande Vitesse) has a ...