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Posted by on Friday, October 11, 2013 at 12:55am.

a train goes into a tunnel at 20m/s and emerges from itat 55m/s. the tunnel is 1500m long.assuming constant acceleration the time for which the train moves in tunnel is

  • physics - , Saturday, October 12, 2013 at 9:20pm

    a=(V^2-Vo^2)/2d
    a=(55^2-20^2)/3000=0.875m/s^2

    V = Vo + a*t
    t = (V-Vo)/a = (55-20)/0.875 = 40 s.

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