Wednesday

October 1, 2014

October 1, 2014

Posted by **Kyle** on Thursday, October 10, 2013 at 10:39pm.

s = −10 + t − 15t2; t = 8

(a) Find the point's acceleration as a function of t.

s''(t)=

I know this answer, it is -30

(b) Find the point's acceleration at the specified time.

s''(8) = I don't know this one

- Brief Calculus -
**Reiny**, Friday, October 11, 2013 at 12:19ams = -10 + t - 15t^2

s' = v = 1 - 30t

s'' = a = -30 , which is a constant

so no matter what value of t you take, e.g. t = 30

there is no variable to sub into, so

a = -30

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