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Brief Calculus

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The position s of a point (in feet) is given as a function of time t (in seconds).

s = −10 + t − 15t2;  t = 8

(a) Find the point's acceleration as a function of t.


I know this answer, it is -30

(b) Find the point's acceleration at the specified time.

s''(8) = I don't know this one

  • Brief Calculus -

    s = -10 + t - 15t^2
    s' = v = 1 - 30t
    s'' = a = -30 , which is a constant

    so no matter what value of t you take, e.g. t = 30
    there is no variable to sub into, so

    a = -30

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