AP physics c
posted by please help on .
A helicopter lifts a 63 kg astronaut 10 m vertically from the ocean by means of a cable. The acceleration of the astronaut is g/10.
(a) How much work is done on the astronaut by the force from the helicopter?
Incorrect: Your answer is incorrect.
J
(b) How much work is done on the astronaut by her weight?
Correct: Your answer is correct.
J
(c)What is the kinetic energy?
J
(d) What is the speed of the astronaut just before she reaches the helicopter?

a. Work = F * d = m*g/10 * d
Work = 63*(9.8/10) * 10 = 617.4 Joules.
b. Work=m*g * d = 63*9.8 * 10 = 6174 J.