An block of mass , starting from rest, slides down an inclined plane of length and angle with respect to the horizontal. The coefficient of kinetic friction between the block and the inclined surface is . At the bottom of the incline, the block slides along a horizontal and rough surface with a coefficient of kinetic friction . The goal of this problem is to find out how far the block slides along the rough surface.

What is the work done by the friction force on the block while it is sliding down the inclined plane? Express your answer in terms of , , , , , and (enter theta for , mu_1 for , and mu_2 for ).



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Answer:



(b) What is the work done by the gravitational force on the block while it is sliding down the inclined plane? Express your answer in terms of , , , , , and (enter theta for , mu_1 for , and mu_2 for ).



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Answer:



(c) What is the kinetic energy of the block just at the bottom of the inclined plane? Express your answer in terms of , , , , , and (enter theta for , mu_1 for , and mu_2 for ).
d) After leaving the incline, the block slides along the rough surface until it comes to rest. How far has it traveled? Express your answer in terms of , , , , , and (enter theta for , mu_1 for , and mu_2 for ).

The height is L sin(theta). The decrease in the gravitational potential energy is thus m g L sin(theta).

The magnitude of the component of the gravitational force orthogonal to the incline is m g cos(theta), therefore the normal force is equal to
m g cos(theta). The friction force is thus equal to mu_1 m g cos(theta), the work done by the friction force is thus:

- mu_1 m g cos(theta) L

the minus sign coming from the fact that the force has a direction oposite to the displacement.

The kinetic energy at the bottom of the incline is thus given by:

m g L [sin(theta) - mu_1 cos(theta)]

Then there is a big mistake in the problem, because it assumes that the block will start to slide on the rough horizontal surface with with an initial velocity that corresponds to the above kinetic energy, but this wrong. I'll explain that later.

If the kinetic energy at the start of the horizntal rough surface is E, then you obviously have that the distance d it will travel satisfies:

mu_2 m g d = E

So, d = E/(mu_2 m g).

Now, you can't take E equal to

m g L [sin(theta) - mu_1 cos(theta)]

because the block has to change direction which requires an extra normal force and therefore additional friction forces. To calculate this effect, let's assume that the change in direction happens on the surface with coefficient of friction mu_1 over a very short distance at the ground level.

Then what happens is that the component of the block in the vertical direction will have to vanish when the incline levels off and the block is about to enter the rough surface. The integral of the component of the normal force in the vertical direction over time during the change of direction is thus equal to p sin(theta) where p is the magnitude of the initial momentum.

The friction force is always orthogonal to the normal force, and equal to mu_1 times that normal force. Therefore the component of the friction force in the horizontal direction is - mu_1 times the component if the normal force in the vertical direction, the integral over time during the change in direction is thus equal to
-mu_1 p sin(theta) and this is then the change in the component of the momentum in the horizontal direction.

The initial kinetic energy was:

E1 =
m g L [sin(theta) - mu_1 cos(theta)]

This is also given in terms of the momentum as:

E1 = p^2/(2m)

therefore:

|p| = sqrt(2 m E1)

the initial horizontal component is thus:

|p| cos(theta) = sqrt(2 m E1) cos(theta)

The final horizontal component is thus:

sqrt(2 m E1)*
[cos(theta) - mu_1 sin(theta)]

and this is the total momentum because the vertical component will have vanished as the incline levels off.

The kinetic energy at the start of the rough surface is thus:

E = E1 [cos(theta) - mu_1 sin(theta)]

The distance the block will slide is thus given by:

d = E/(mu_2 m g) =

L/mu_2 [cos(theta) - mu_1 sin(theta)]*

[sin(theta) - mu_1 cos(theta)] =

[1/2(1+mu_1^2)sin(2 theta)-mu_1]L/mu_2

Correction of the last part:

The kinetic energy at the start of the rough surface is thus:

E = E1 [cos(theta) - mu_1 sin(theta)]^2

The distance the block will slide is thus given by:

d = E/(mu_2 m g) =

L/mu_2 [cos(theta) - mu_1 sin(theta)]^2* [sin(theta) - mu_1 cos(theta)] =

[1/2(1+mu_1^2)sin(2 theta)-mu_1]*
[cos(theta) - mu_1 sin(theta)] L/mu_2

u r a genious man..!

To solve this problem, we will break it down into smaller steps and use the principles of work and energy.

(a) The work done by the friction force on the block while it is sliding down the inclined plane can be calculated using the equation:

Work = Force x Distance

The force of kinetic friction can be calculated using the equation:

Force of friction = coefficient of kinetic friction * normal force

The normal force can be calculated using the equation:

Normal force = mass x gravitational field strength x cos(theta)

Therefore, the work done by the friction force is:

Work = (coefficient of kinetic friction * mass * gravitational field strength * cos(theta)) x distance

Substitute the given values into the equation to find the work done by the friction force.

(b) The work done by the gravitational force on the block while it is sliding down the inclined plane can be calculated using the equation:

Work = Force x Distance

The force of gravity can be calculated using the equation:

Force of gravity = mass x gravitational field strength x sin(theta)

Therefore, the work done by the gravitational force is:

Work = (mass * gravitational field strength * sin(theta)) x distance

Substitute the given values into the equation to find the work done by the gravitational force.

(c) The kinetic energy of the block just at the bottom of the inclined plane can be calculated using the equation:

Kinetic energy = 0.5 * mass * velocity^2

The velocity can be calculated using the principle of conservation of energy, where the potential energy at the top of the inclined plane is converted to kinetic energy at the bottom. The potential energy at the top of the inclined plane can be calculated using the equation:

Potential energy = mass * gravitational field strength * distance * sin(theta)

Set the potential energy equal to the kinetic energy and solve for velocity. Then substitute the velocity into the kinetic energy equation to find the kinetic energy of the block at the bottom of the inclined plane.

(d) To find how far the block travels along the rough surface until it comes to rest, we can use the work-energy principle. The work done by the friction force on the block is equal to the change in kinetic energy of the block. The work done by the friction force can be calculated using the equation:

Work = Force x Distance

The force of kinetic friction on the rough surface can be calculated using the equation:

Force of friction = coefficient of kinetic friction on the rough surface * normal force

The normal force can be calculated using the equation:

Normal force = mass x gravitational field strength

Therefore, the work done by the friction force is:

Work = (coefficient of kinetic friction on the rough surface * mass * gravitational field strength) x distance

Set the work done by the friction force equal to the change in kinetic energy and solve for distance. Substitute the given values into the equation to find the distance traveled by the block.