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March 2, 2015

March 2, 2015

Posted by **Lindsay** on Thursday, October 10, 2013 at 4:09pm.

f(x)=x^3-9x, [-3,3]

- Calculus -
**Graham**, Thursday, October 10, 2013 at 4:46pmf(x) is continuous over the domain. [-3,3]

f(x) is differential.

f'(x) = 3x^{2}-9

f(x) has two equal value points on the independent axis.

f(-3) = f(3) = 0

Therefore Rolle's Theorem Applies

.: Exists c such that f'(c)=0

Solve for c:

0 = 3c^{2}- 9

...

- Calculus -
**Me**, Thursday, October 10, 2013 at 5:01pmAhh! That's the answer I had but I was doubting it because my partner got something else! Thanks!

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