Can you check these percent proportion problems?
1. 50 students got pizza at lunch. 20% of those got chocolate milk. How many students got chocolate milk?
50/n = 20/100
20n = 100*50
20n = 5000
n = 5000/20
n = 250 students
2. Mr. Ford has 45 fish in his aquarium. What is the number of blue fish if 40% of the fish are blue?
n/45 = 40/100
100n = 45*40
100n = 1800
n = 1800/100
n = 18 fish
3. In a survey 30 out of 40 people said they like carving pumpkins during all season. What is the percent of people who like to carve pumpkins?
30/40 = p/100
40p = 30*100
40p = 3000
p = 3000/40
p = 75%
4. In a dog park, 80% of the dogs were on leashes. If 20 dogs were on leashes, then how many dogs were in the park?
20/d = 80/100
80d = 20*100
80d = 2000
d = 2000/80
d = 25 dogs
Unit Rate/Ratios
1. Mr. Santana was buying some candy for his classes. When he went to buy some Crunch bars, he found 2 different packages:
3.6 oz for $1
11.5 oz for $2.50
Which is the better buy?
Answer: seems like it would 11.5oz because getting more in the bag. But, not sure how to put this is in a proportion.
1. You have to just multiply them, because it says 20% of those 50 students got milk, so
50 * 0.2 = 10 students
2. Yep
3. Yep
4. Yep
5. [Unit ratio]
What we'll do here is to get the cost per oz. Thus we divide $1 by 3.6 oz and $2.50 by 11.5 oz, then compare.
$1/3.6 = $0.278 / oz
$2.5/11.5 = $0.217 / oz
Thus the second option is better.
Hope this helps~ :3
Thanks!! Yes, this helps.
To determine which package is the better buy, you can calculate the unit rate for each package, which is the cost per ounce.
For the first package, the unit rate is $1 for 3.6 ounces, so the cost per ounce is:
1 dollar / 3.6 ounces = 0.28 dollars/ounce
For the second package, the unit rate is $2.50 for 11.5 ounces, so the cost per ounce is:
2.50 dollars / 11.5 ounces = 0.22 dollars/ounce
Comparing the two unit rates, you can see that the second package has a lower cost per ounce. Therefore, the 11.5 oz package for $2.50 is the better buy as you are getting more candy per dollar spent.