A 23.9kg box rests on a table. A 16 kg box is placed on top of the first box, as shown. determine the total in N that the table exerts on the first box.
To determine the total force that the table exerts on the first box, we need to consider the forces acting on the system. According to Newton's third law, every action has an equal and opposite reaction. In this case, the force that the second box exerts on the first box is equal in magnitude and opposite in direction to the force that the first box exerts on the second box.
Given that the first box has a mass of 23.9 kg and the second box has a mass of 16 kg, we can find the total force exerted on the first box by considering the weight of both boxes.
The weight of an object can be calculated using the formula:
Weight = mass * acceleration due to gravity
where the acceleration due to gravity is approximately 9.8 m/s^2.
So, the weight of the first box is:
Weight1 = mass1 * acceleration due to gravity
= 23.9 kg * 9.8 m/s^2
And the weight of the second box is:
Weight2 = mass2 * acceleration due to gravity
= 16 kg * 9.8 m/s^2
According to Newton's third law, the force that the table exerts on the first box is equal in magnitude and opposite in direction to the force that the first box exerts on the second box. Therefore, the total force exerted on the first box by the table is the sum of the weights of both boxes.
Total force on the first box = Weight1 + Weight2
Calculating this, we get:
Total force on the first box = (23.9 kg * 9.8 m/s^2) + (16 kg * 9.8 m/s^2)
Simplifying further:
Total force on the first box = 234.22 N + 156.8 N
= 391.02 N
So, the table exerts a total force of 391.02 N on the first box.