PLEASE HELP.

If I have 0.10 mL of 200 mcg/mL protein, 0.90 mL of distilled water, and 2.00 mL of Bradford reagent, what is the concentration of the protein?

200 mcg/mL protein x 0.10 mL = 20 mcg protein. You place that into a total volume of

0.10 mL + 0.90 mL + 2.00 mL so that 20 mcg is now in 3.00 mL (assuming the volumes are additive. Technically they are not but with such dilute solutions the difference is not enough to worry about.)
New concn protein is 20 mcg/3.00 mL = about 6.67 mcg/mL.

Thank you so much!

To determine the concentration of the protein, you need to consider the dilution of the protein solution with distilled water and the volume of the Bradford reagent. Here's how you can calculate it:

1. Start by calculating the total volume of the protein solution. Add the volumes of the protein and the distilled water:

Total volume = Volume of protein + Volume of distilled water
Total volume = 0.10 mL + 0.90 mL
Total volume = 1.00 mL

2. Next, you need to calculate the dilution factor. The dilution factor represents the fold by which the original solution is diluted. In this case, the original protein concentration is 200 mcg/mL, and it is diluted to a total volume of 1.00 mL:

Dilution factor = Total volume / Volume of protein
Dilution factor = 1.00 mL / 0.10 mL
Dilution factor = 10

3. Now, you can calculate the concentration of the protein by dividing the original concentration by the dilution factor:

Protein concentration = Original concentration / Dilution factor
Protein concentration = 200 mcg/mL / 10
Protein concentration = 20 mcg/mL

Therefore, the concentration of the protein is 20 mcg/mL.