Solve 2x - 3y = 9 for y.
Solve 2a + ab = c for a.
Solve 2s - k = 11 for k?
-3y = -2x + 9
y = -2/-3x - 3
Try the others now.
I have but I don't remeber how.
Do it the same way.
To solve any linear equation in x and y for y takes 2 steps
1. move all terms except the y term to the right
-3y = -2x + 9
2. divide each term by the coefficient of the y term
y = (-2/-3)x + 9/-3
y = (2/3)x - 3
Can anyone provide the steps of solving these equations? I am truly struggling.
Reiny gave you these steps.
I don't understand what steps must be taken in order to solve the other equations.
I know it is the same process but I an still very confused.
2x - 3y = 9
Subtract 2x from both sides. Now, you want this in the form of y = mx + b. So, I will write this as -3y = -2x (since you subtract) + 9 (since we know 9 is positive).
-3y = -2x + 9
Now, divide all terms by -3.
y = -2/-3x (or 2/3x like Reiny showed) - 3 (because 9 / -3 = -3)
y = 2/3x - 3