Tuesday

September 16, 2014

September 16, 2014

Posted by **Maddie** on Monday, October 7, 2013 at 8:41pm.

I tried 2mgh=1/2mv^2 so that the mass would cancel out and then i solved for h and used that number in the equation v^2=V(o)^2+2a(h) and I am not getting the correct answer... any help would be greatly appreciated! thank you

- Physics -
**Elena**, Tuesday, October 8, 2013 at 3:03pmv=gt

t=v/g =20/9.8 =2.04 s

h=gt²/2 =9.8•2.04²/2 =20.4 m

h=(v²-v₀²)/2g

v=sqrt{2gh+ v₀²} =sqrt{2•9.8•20.4 +20²}=

=28.3 m/s

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