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physics

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A baseball is hit at a height of 1.1 m with an unknown initial velocity at 38 ° above the horizontal. It just clears a barrier of height 36.1 m at a horizontal distance of 63.0 m. Find:

a) the initial speed;

  • physics - ,

    Range = Vo^2*sin(2A)/g = 63 m.
    Vo^2*sin(76)/9.8 = 63
    0.0990Vo^2 = 63
    Vo^2 = 636.3
    Vo = 25.23 m/s[38o]

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