A lab tech had accidentally set out 16M HCl for this experiment. How much ( in mL) 16M HCl is needed to make 450mL of a 3M HCl solution?
c1v1 = c2v2
c = concn
v = volume
16M x ?mL = 3M x 450 mL
Solve for mL.
67
To determine how much 16M HCl is needed to make a 3M HCl solution, we can use the formula for dilution:
(C1)(V1) = (C2)(V2)
Where:
C1 = initial concentration of the solution
V1 = initial volume of the solution
C2 = final concentration of the solution
V2 = final volume of the solution
In this case, the initial concentration (C1) is 16M, the initial volume (V1) is unknown, the final concentration (C2) is 3M, and the final volume (V2) is 450mL.
Substituting the values into the formula, we get:
(16M)(V1) = (3M)(450mL)
To solve for V1, we divide both sides of the equation by 16M:
V1 = (3M)(450mL) / 16M
Simplifying the equation, we find:
V1 = 84.375 mL
Therefore, to make a 3M HCl solution, 84.375 mL of 16M HCl is needed.