Posted by Mary Ann on Monday, October 7, 2013 at 10:24am.
I need help I don't know how to solve this system
Solve the following system. Show all your work
3x2y+2z= 30
x+3y4z= 33
2x4y+3z= 42

Algebra, help needed  Steve, Monday, October 7, 2013 at 12:03pm
what makes it especially difficult? You must have solved similar systems already.
2(1st)+(2nd) and 3(1st)2(3rd):
5x  y = 27
5x + 2y = 6
Now it gets easier:
3y = 21
y = 7
so,
x = 4
z = 2

Algebra, help needed  Mary Ann, Monday, October 7, 2013 at 12:19pm
every time i try adding two equations that could make it simpler ex; by adding and crossing out variables. i just could never get it right and still have those three same variables thx for the help

Algebra, help needed  Steve, Monday, October 7, 2013 at 12:27pm
Yeah, it takes a bit of practice. Look for LCMs to get rid of stuff. In this case, since 3*2=6, we had to take 3 times the 1st to get 6 and 2 times the 3rd to get 6.
Usually the errors come in watching the other coefficients. In the beginning, it helps to write everything down so details don't get lost.

Algebra, help needed  kendra, Monday, October 7, 2013 at 6:31pm
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