posted by Jason on .
If 5.300 g of C6H6 is burned and the heat produced from the burning is added to 5691 g of water at 21 °C, what is the final temperature of the water?
2C6H6(l) +15O2 (g)----> 12CO2(g)+6H2O(l) +6542
Heat produced by 5.20 g C6H6 is
6542 WHAT. Joules? kJ? I will assume J and you can make th adjustment.
6542 J x (5.30/2*molar mass C6H6 = ? J or kJ. If kJ change to J.
Then q = J = = mass H2O x specific heat H2O x (Tfinial-Tinitial).
Subtitute and solve for Tfinal