Find the unknown in the following equation. If there are more than one solution, then separate the solutions with a comma.
(−8y−4)^2+10=14
y=?
I keep on getting y=-0.5, is that correct?
well, does it satisfy the equation?
(-8(-.5)-4)^2+10
= (4-4)^2+10
= 0+10
= 10
BZZZZT!
Try this:
(−8y−4)^2+10=14
(−8y−4)^2=4
-8y-4 = ±2
-8y = 4±2 = 6 or 2
y = -6/8 or -2/8
y = -3/4 or -1/4
Nope, -1/2 is not a solution
thanks I figured out what I did wrong
To find the unknown in the equation (−8y−4)^2 + 10 = 14, you need to solve for y. Let's go step by step:
1. Start by subtracting 10 from both sides of the equation:
(−8y−4)^2 = 14 - 10
(−8y−4)^2 = 4
2. Take the square root of both sides of the equation to remove the squaring:
√[(−8y−4)^2] = √4
-8y - 4 = ±2
3. Now, we have two separate equations:
-8y - 4 = 2 and -8y - 4 = -2
4. Solve the first equation:
-8y - 4 = 2
-8y = 2 + 4
-8y = 6
y = 6/-8
y = -0.75
5. Solve the second equation:
-8y - 4 = -2
-8y = -2 + 4
-8y = 2
y = 2/-8
y = -0.25
Therefore, the solutions for y are y = -0.75 and y = -0.25. There are two solutions, so we separate them with a comma.