Tuesday

September 2, 2014

September 2, 2014

Posted by **Anonymous** on Sunday, October 6, 2013 at 8:16am.

(a) At what time after the first stone is thrown will the two stones be at the same altitude above ground? (in seconds)

- Physics -
**Henry**, Tuesday, October 8, 2013 at 5:45pma. h1 = V1*t + 0.5g*t^2

h1 = 11*1 - 5*1^2 = 6 m. Head start.

V^2 = V1^2 + 2g*h

V^2 = 11^2 - 20*6 = 1

V = 1.0 m/s.

h2=V2*t + 0.5g*t^2 = 6 + V*t + 0.5g*t^2

16*t - 5*t^2 = 6 + 1*t - 0.5g*t^2

The 0.5g*t^2 terms cancel:

16t - t = 6

15t = 6.0

t = 0.4 s. to catch up.

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