Posted by **Anonymous** on Sunday, October 6, 2013 at 8:16am.

A stone is thrown up vertically from the ground (the gravitational acceleration is g = 10 m/s^2 ). After a time dt =1 s, a second stone is thrown up vertically. The first stone has an initial speed v1 = 11.0 m/s, and the second stone v2 = 16.0 m/s.

(a) At what time after the first stone is thrown will the two stones be at the same altitude above ground? (in seconds)

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