How many milliliters of 0.4N NaOH can be made from 20ml of 2N solution

5 ml

To find out how many milliliters of 0.4N NaOH can be made from 20ml of 2N solution, we can use the concept of equivalence of moles of acid to moles of base.

First, let's determine the number of moles of NaOH present in the 20ml of 2N solution:

Moles of NaOH = Normality (N) × Volume (in liters)
Moles of NaOH = 2N × (20ml / 1000ml) (since 1 liter = 1000ml)
Moles of NaOH = 0.04 moles

Since we want to prepare a 0.4N solution, we need to find the volume of 0.4N NaOH solution containing 0.04 moles of NaOH.

Volume (in liters) = Moles / Normality
Volume (in liters) = 0.04 moles / 0.4N
Volume (in liters) = 0.1 liters

Finally, we convert the volume from liters to milliliters:

Volume (in milliliters) = Volume (in liters) × 1000
Volume (in milliliters) = 0.1 liters × 1000
Volume (in milliliters) = 100 ml

So, from 20ml of 2N NaOH solution, we can make 100ml of 0.4N NaOH solution.

To determine how many milliliters of 0.4N NaOH can be made from 20ml of a 2N solution, we need to use the concept of normality (N).

Normality is a measure of the concentration of a solution and represents the number of equivalents of a solute (in this case, NaOH) per liter of solution. The formula to calculate normality is:

Normality (N) = (Molarity (M) x Number of equivalents) / Volume of solution (L)

The number of equivalents is determined by the balanced chemical equation of the reaction involving the solute. In this case, NaOH has one equivalent because it donates one hydroxide (OH-) ion.

To calculate the milliliters of 0.4N NaOH that can be made from 20ml of 2N NaOH solution, we need to use the formula mentioned above.

Given:
Volume of the 2N NaOH solution (V1) = 20 ml
Normality of the 2N NaOH solution (N1) = 2N
Desired normality of the diluted NaOH solution (N2) = 0.4N

Let's calculate the volume of the diluted NaOH solution (V2) using the formula:

(V1 x N1) = (V2 x N2)

Substituting the given values:

(20 ml x 2N) = (V2 x 0.4N)

Now, solve for V2:

(20 x 2) / 0.4 = V2

V2 = 100 ml

Therefore, 100 milliliters of 0.4N NaOH can be made from 20 ml of 2N NaOH solution.