Posted by **ray** on Friday, October 4, 2013 at 11:14pm.

identify the vertex and the axis of symmetry of the graph for the function y=3(x+2)^2

a.vertex(2,-3

axis of symmetry x=2

b.vertex(-2,-3)

axis of symmetry x=-2

c.vertex(2,3)

axis of symmetry x=2

d.vertex(-2,3)

axis of symmetry x=-2

identify the maximum or minimum value and the domain and range of the graph of the function y=2(x-3)^2-4.

a.minimum value -4

domain all real numbers

range all real numbers_>_-4

b.max value 4

domain all real numbers

range all real numbers_<_4

c. max value -4

domain all real numbers_<_-4

range all real numbers

d. minimum value 4

domain all real numbers_>_4

range all real numbers

please i need some help guys thanks

- URGENT ALGEBRA 2 -
**Steve**, Friday, October 4, 2013 at 11:22pm
if you know that

y = a(x-h)^2 + k

has axis of symmetry at x=h

and vertex at (h,k)

all polynomials have domain of all reals numbers

you are home free.

- URGENT ALGEBRA 2 -
**ray**, Friday, October 4, 2013 at 11:24pm
well yeah but ive had this question on a past test and i don't know the answer and i keep getting it wrong can you please help me answer it correctly?

- URGENT ALGEBRA 2 -
**johnny**, Friday, October 4, 2013 at 11:30pm
im not sure steve should be able to give you the answer im stumped on this one to ray

- URGENT ALGEBRA 2 -
**Steve**, Saturday, October 5, 2013 at 5:56am
identify the vertex and the axis of symmetry of the graph for the function y=3(x+2)^2

vertex at (-2,0)

axis: x = -2

Looks like a typo or a bad set of answers

If it was y = 3 + (x+2)^2

then the vertex is at (-2,3)

identify the maximum or minimum value and the domain and range of the graph of the function y=2(x-3)^2-4.

vertex at (3,-4)

axis: x=3

minimum at vertex: y = -4

domain all reals

range: all reals >= -4 (where the vertex is)

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