Posted by jasmine on Friday, October 4, 2013 at 1:20pm.
A 4.00 bucket of water is accelerated upward by a cord of negligible mass whose breaking strength is 78.0 . If the bucket starts from rest, what is the minimum time required to raise the bucket a vertical distance of 10.0 without breaking the cord?

physics  Elena, Friday, October 4, 2013 at 2:09pm
ma=Tmg
a=(T/m)g= 19.5 – 9.8 = 9.7 m/s²
h=at²/2=>
t=2h/a = 2•10/9.7 = 2.06 s.

physics  Juan, Friday, January 30, 2015 at 6:42am
the above solution is correct except for the very last part. They did not take into account that it should have been:
t^2=(2h/a)
sqrt(t^2)=sqrt(2.06)
t=1.44
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