Posted by **jasmine** on Friday, October 4, 2013 at 1:20pm.

A 4.00 bucket of water is accelerated upward by a cord of negligible mass whose breaking strength is 78.0 . If the bucket starts from rest, what is the minimum time required to raise the bucket a vertical distance of 10.0 without breaking the cord?

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**Elena**, Friday, October 4, 2013 at 2:09pm
ma=T-mg

a=(T/m)-g= 19.5 – 9.8 = 9.7 m/s²

h=at²/2=>

t=2h/a = 2•10/9.7 = 2.06 s.

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**Juan**, Friday, January 30, 2015 at 6:42am
the above solution is correct except for the very last part. They did not take into account that it should have been:

t^2=(2h/a)

sqrt(t^2)=sqrt(2.06)

t=1.44

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