College Algebra
posted by Diane on .
A rancher wishes to enclose a rectangular partitioned corral with 1932 feet of fencing. What dimensions of the corral would enclose the largest possible area? Find the maxium area.

Didn't you read my answer to your question?
http://www.jiskha.com/display.cgi?id=1380904270 
The largest area would be closest to a square. Divide 1932 by 4.

I tried that answer and it didn't work, the question wants the dimensions of the corral: length and width.

Try PsyDAG's answer.

Tried that too and still didn't work. the picture has a rectangular fence with a fence going across the middle from longest side to the opposite side.

well, if you want a correct answer, you need to pose the correct question. If the short side is x and the long side is y, then
2y+3x = 1932, so y = (19323x)/2
area = xy = x(19323x)/2 = (1932x3x^2)/2
This is a parabola, with vertex at x=322.
You can probably take it from there. Note that just as PsyDiag suggested, the fencing is evenly divided between length and width. 
thank you Steve, that helped alot! appreciate your help.