Posted by Diane on Friday, October 4, 2013 at 12:54pm.
A rancher wishes to enclose a rectangular partitioned corral with 1932 feet of fencing. What dimensions of the corral would enclose the largest possible area? Find the maxium area.

College Algebra  Ms. Sue, Friday, October 4, 2013 at 12:57pm
Didn't you read my answer to your question?
http://www.jiskha.com/display.cgi?id=1380904270

College Algebra  PsyDAG, Friday, October 4, 2013 at 12:58pm
The largest area would be closest to a square. Divide 1932 by 4.

College Algebra  Diane, Friday, October 4, 2013 at 1:00pm
I tried that answer and it didn't work, the question wants the dimensions of the corral: length and width.

College Algebra  Ms. Sue, Friday, October 4, 2013 at 1:01pm
Try PsyDAG's answer.

College Algebra  Diane, Friday, October 4, 2013 at 1:04pm
Tried that too and still didn't work. the picture has a rectangular fence with a fence going across the middle from longest side to the opposite side.

College Algebra  Steve, Friday, October 4, 2013 at 3:27pm
well, if you want a correct answer, you need to pose the correct question. If the short side is x and the long side is y, then
2y+3x = 1932, so y = (19323x)/2
area = xy = x(19323x)/2 = (1932x3x^2)/2
This is a parabola, with vertex at x=322.
You can probably take it from there. Note that just as PsyDiag suggested, the fencing is evenly divided between length and width.

College Algebra  Diane, Friday, October 4, 2013 at 3:51pm
thank you Steve, that helped alot! appreciate your help.
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