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March 3, 2015

March 3, 2015

Posted by **Sandra** on Friday, October 4, 2013 at 10:20am.

- statistics -
**MathGuru**, Friday, October 4, 2013 at 7:51pmMean = np

SD = √npq

n = 200

p = 1/6

q = 1 - p = 5/6

Therefore:

Mean = 200(1/6) = 33.33

SD = √[200(1/6)(5/6)] = 5.27

Use z-scores:

z = (x - mean)/SD

z = (30 - 33.33)/5.27 = -0.63

Check a z-table for the probability.

(Remember the problem is asking "at most 30" when looking at the table.)

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