Thursday

July 31, 2014

July 31, 2014

Posted by **Sandra** on Friday, October 4, 2013 at 10:20am.

- statistics -
**MathGuru**, Friday, October 4, 2013 at 7:51pmMean = np

SD = √npq

n = 200

p = 1/6

q = 1 - p = 5/6

Therefore:

Mean = 200(1/6) = 33.33

SD = √[200(1/6)(5/6)] = 5.27

Use z-scores:

z = (x - mean)/SD

z = (30 - 33.33)/5.27 = -0.63

Check a z-table for the probability.

(Remember the problem is asking "at most 30" when looking at the table.)

**Related Questions**

Statistics - DIAGRAMS MUST BE DRAWN Given the standard normal distribution, ...

statistics - use the normal distribution to approximate the desired probability...

statistics - Use of normal distribution to approximate the desired probability. ...

Probability and Statistics (Continuation) - Assume 10% of the engines ...

Probability and Statistics - An oil prospector will drill a succession of holes ...

statistics - mean cholesterol is 175mg/dl..standard deviation =20mg/dl assume ...

statistics - without the use of the standard normal tables, should techniques of...

Business Statistics - In each case, sketch the two speciﬁed normal curves...

statistics - If Z is a standard normal variable, find the probability that Z ...

statistics - Information given:the distribution of male head circumference (HC) ...