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February 28, 2015

February 28, 2015

Posted by **Arin** on Friday, October 4, 2013 at 12:19am.

- Calculus -
**Steve**, Friday, October 4, 2013 at 12:21amv = 3t^2-12t+9

= 3(t-3)(t-1)

a = 6t-12

so find a at t=1,3

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