Posted by confused on .
3 persons are to divide among themselves 21 equal cask, of which 7 are full, 7 are half full, and 7 are empty. how can an equitable division be made, without pouring the wine from any cask into any other, in such a way that each person receives the same amount of wine and the same total number of casks? is there more than one way to accomplish this division

problem solving  math 
Steve,
there are 7(1+1/2) = 21/2 casks of wine
Each person must thus get 7/2 = 3 1/2 casks
So, give 3 full and 1 half casks to two people, leaving
1 full and 5 half casks (3 1/2) for the 3rd person