A powerful motorcycle can produce an acceleration of 3.5 m/s2 while traveling at 90 km/h. At that speed the forces resisting motion, including friction and air resistance, total 400 N. (Air resistance is analogous to air friction. It always opposes the motion of an object.)
a.)What force does the motorcycle exert backward on the ground to produce its acceleration if the mass of the motorcycle with rider is 255 kg?
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To determine the force exerted backward on the ground by the motorcycle, we need to use Newton's second law of motion, which states that the force (F) is equal to the mass (m) multiplied by the acceleration (a).
In this case, the given value of acceleration (a) is 3.5 m/s², and the given mass (m) of the motorcycle with rider is 255 kg. Therefore, we can use the formula:
F = m * a
Plugging in the given values, we have:
F = 255 kg * 3.5 m/s²
Now, we can calculate the force:
F = 892.5 N
Therefore, the motorcycle exerts a force of 892.5 N backward on the ground to produce its acceleration.